How to Find 2 Consecutive Even Integers Whose Product is 168? 3 Methods

Calculator: Find 2 consecutive even integers whose product is

Result:
Verify:

Related calculator

Latest solutions

What are Two Consecutive Odd Integers Whose Product is 483?

How to Find 2 Consecutive Even Integers Whose Product is 120?

What are Three Consecutive Integers Whose Product is 504?

What are Three Consecutive Integers Whose Product is 210?

How to Find 3 Consecutive Integers Whose Product is 120? 3 Methods

What are Two Consecutive Integers Whose Product is 4032?

What are Two Consecutive Integers Whose Product is 306?

How to Find 2 Consecutive Integers Whose Product is 240?

What Are Two Consecutive Integers Whose Product is 182?

The product of 2 consecutive even integers is 168, what are these 2 even integers? The answer are 12 and 14. How to find these 2 consecutive even integers whose product is 168? Here are three methods, especially the third method, which can be easily calculated without the help of other tools. Let’s introduce them one by one.

How to find 2 consecutive even integers whose product is 168?

Method 1: Assumption Method

This is a common mathematical solution. Assuming that 2 * N is used to represent the first even integer, so the second even integer is 2 * N + 2.

Now, the product of 2 consecutive even integers is 168, which can be expressed by equation

2 * N * (2 * N + 2) = 168

Solving equations

2 * N * (2 * N + 2) = 168

4 * N2 + 4 * N = 168

4 * N2 + 4 * N – 168 = 0

N2 + N – 42 = 0

(N – 6) * (N + 7) = 0

N = 6 or N = -7

So, 2 * N = 12 or -14

You can see that the first even integer has 2 values 12 and -14. So, The second even integer also has two values, 14 and -12.

Let’s verify whether the answer is correct?

The first set 12 and 14.

12 * 14 = 168. Correct.

Then let’s verify the second set of answers -14 and -12.

-14 * -12 = 168. This is also eligible.

So, there are two answers of 2 consecutive even integers whose product is 168, one set is 12 and 14, the other set is -14 and -12.

The key to this method is to solve the quadratic equation. If you are not familiar with quadratic equations, the second or third method is recommended. Now we will introduce the second method.

Method 2: Root Sign Method

According to the definition of the root sign, if An = B, then A is the nth root of B to the nth power. An is the multiplication of n identical A.

Now, we need to find 2 consecutive even integers whose product is 168, which can be regarded as the product of 2 identical numbers is 168. That is, find the 2nd root of 168. As long as we find this number, we can use this number as the fulcrum to find the consecutive even integers that meet the conditions.

The equation is as follows

A2 = 168

With the help of the root calculator, you can easily calculate A = 12.96, round down to an even integer A = 12.

The product of 2 consecutive even integers is 168, one even integer is 12, the other even integer is 168 / 12 = 14.

12 and 14 are just two adjacent even integers, which meet the requirements.

12 and 14 are positive integers. If their negative integers are taken, will their product be 168?

-14 * -12 = 168.

Yes, -14 and -12 are also the answer of 2 consecutive even integers whose product is 168.

So, there are two answers of 2 consecutive even integers whose product is 168, one set is 12 and 14, the other set is -14 and -12. The result is the same as the first method.

Obviously, this method needs to calculate the 2nd root first. If you can’t calculate the 2nd root manually, you need to use a root calculator to calculate it. What if there is no such auxiliary tool? It doesn’t matter, let’s move on to the third method.

Method 3: Divisor Method

First of all, we must understand what is divisor. The divisor is also called a factor. If A is divisible by B, B is called A divisor.

Obviously, the product of 2 consecutive even integers is 168, so these 2 consecutive even integers are all divisors of 168. How to find these divisor numbers? First, decompose 168 with the smallest divisor more than 1, and then decompose the obtained quotient until the quotient can no longer be decomposed. Note that the indecomposable here means that no other divisor can be found except 1 and itself. This means that the final quotient is a prime number.

Back to the question: find 2 consecutive even integers whose product is 168.

  • The first step, decompose 168 by the smallest divisor except 1. 168 / 2 = 84;
  • The second step, 84 is decomposed by the smallest divisor except 1. 84 / 2 = 42;
  • The third step, 42 is decomposed by the smallest divisor except 1. 42 / 2 = 21;

By analogy, the following equation is obtained

168
= 2 * 84
= 2 * 2 * 42
= 2 * 2 * 2 * 21
= 2 * 2 * 2 * 3 * 7

Next, group the obtained divisors. Here, you need to divide the last row of numbers 2 * 2 * 2 * 3 * 7 into 2 groups. Obviously, one group is 2 * 7 = 14, the other group is 2 * 2 * 3 = 12.

So, 12 and 14 are the answer of 2 consecutive even integers whose product is 168.

As with the second method, discuss the negative numbers to get another answer -14 and -12.

Is not it simple? The whole process does not require any tools at all. Of course, if you have any questions about the grouping process, please refer to another article Consecutive Integers Calculator Based On A Given Product

FAQS

Now, we have found that the product of 2 consecutive even integers is 168, some problems can be solved by the way.

  • 1. What are two consecutive even integers whose product is 168?
    There are two answers of two consecutive even integers whose product is 168, one set is 12 and 14, the other set is -14 and -12.
  • 2. What is the smaller of two consecutive even integers whose product is 168?
    The smaller positive integer is 12. The smaller negative integer is -14.
  • 3. What is the greater of two consecutive even integers whose product is 168?
    The greater positive integer is 14. The greater negative integer is -12.
  • 4. What is the average of two consecutive even positive integers whose product is 168?
    The average of these 2 consecutive even positive integers is (12 + 14) / 2 = 26 / 2 = 13.
  • 5. What is the sum of two consecutive even positive integers whose product is 168?
    The product of 2 consecutive even positive integers is 168, the sum of them is 12 + 14 = 26.
  • 6. What is the sum of square of two consecutive even positive integers whose product is 168?
    The product of 2 consecutive even integers is 168, the sum of their squares is 122 + 142 = 340.

Conclusion

The above provides three methods to find 2 consecutive even integers whose product is 168. To rank these three methods, I still like the third method. Although the steps are a bit long, the overall calculation difficulty is very small, which is very suitable for a manual calculation. The second method is suitable for those with a root calculator.

In addition, there is one of the easiest way: directly use the calculator provided on this page to find 2 consecutive even integers based on the product. It can eliminate all calculation steps and get the answer directly, which is very convenient and suitable for everyone!

Of course, if the number of consecutive even integers you want to calculate is not 2, or if you need to calculate consecutive integers or consecutive odd integers. It is recommended to use our more advanced product-based consecutive integers calculator, where you can specify the number of integers and Integer type. I believe it can meet your requirements.

Well, the above is all about finding 2 consecutive even integers whose product is 168. Please leave a message and tell me, which one of the three methods do you like?

Leave a Reply

Back to top of page