# Find Four Consecutive Integers Whose Sum is 198 by 3 Ways

Result:
Verify:

## Latest solutions

Find Four Consecutive Even Integers Whose Sum is 8012 by 3 Ways

Find Four Consecutive Integers Whose Sum is 114 by 3 Ways

Find Three Consecutive Integers Whose Sum is 108 by 3 Ways

Find Four Consecutive Integers Whose Sum is 106 by 3 Ways

Find Three Consecutive Integers Whose Sum is 96 by 3 Ways

Find Three Consecutive Integers Whose Sum is 87 by 3 Ways

Find Three Consecutive Integers Whose Sum is 78 by 3 Ways

Find Three Consecutive Integers Whose Sum is 75 by 3 Ways

Find Four Consecutive Integers Whose Sum is 74 by 3 Ways

The sum of four consecutive integers is 198, what the integers? I can easily tell you that the answer are 48, 49, 50 and 51. You must be interested in how to find these 4 consecutive integers whose sum is 198. There are three methods here, let us introduce them one by one below.

## 1. Find four consecutive integers whose sum is 198 by hypothetical method

Assuming that N is used to represent the first integer, so the second integer is N + 1, the third integer is N + 2, the 4th integer is N + 3.

Therefore, the sum of 4 consecutive integers is 198, which can be expressed by the equation

N + (N + 1) + (N + 2) + (N + 3) = 198

Solve this equation

N + (N + 1) + (N + 2) + (N + 3) = 198

N + N + 1 + N + 2 + N + 3 = 198

4 * N + 1 + 2 + 3 = 198

4 * N + 6 = 198

4 * N = 198 – 6

4 * N = 192

N = 192 / 4

N = 48

Now, we can get that 48 is the first integer of 4 consecutive integers whose sum is 198. So, the second integer is 49, the third integer is 50, the 4th integer is 51.

The answer came out, the sum of 4 consecutive integers is 198, these three integers are 48, 49, 50 and 51.

Verify: 48 + 49 + 50 + 51 = 198. Correct!

This is the most common method, let’s look at the second method, which is my favorite method.

## 2. Find four consecutive integers whose sum is 198 by formula method

According to the consecutive integers calculator based on sum, we can know that the sum of M consecutive integers is S, the first integer formula is

First(n) = S / M – (M – 1) / 2

M represents the number of consecutive integers.

S stands for sum.

Back to the problem we want to solve: find four consecutive integers whose sum is 198. In here, M = 4, S = 198. Replace them in the formula to calculate the first integer

First(n) = 198 / 4 – (4 – 1) / 2 = 49.5 – (4 – 1) / 2 = 49.5 – 3 / 2 = 49.5 – 1.5 = 48

The first integer is 48, so, it can be easily calculated that the second integer is 49, the third integer is 50, the 4th integer is 51.

Thus, the answer are also 48, 49, 50 and 51. Same as the first method. Then look at the third method, which is the simplest one.

## 3. Find four consecutive integers whose sum is 198 by average method

The principle is very simple, because we want to calculate the consecutive integers, so after calculating the average, we can find the integers near the average.

The sum of 4 consecutive integers is 198, so, the average of these 4 consecutive integers is 198 / 4 = 49.5. The integers around 49.5 are 45, 46, 47, 48, 49, 50, 51, 52, 53. Now the problem is simple, find 4 consecutive integers from 45 to 53 and their average is 49.5. The answer are 48, 49, 50 and 51.

So the sum of 4 consecutive integers is 198, these integers are 48, 49, 50, 51. The results are consistent with the above two methods. Is it very simple?

## Problems can be sloved by this answer

Now, we have found out these 4 consecutive integers whose sum is 198, some problems can be easily solved.

• The sum of four consecutive integers is 198, the smallest one is 48.
• The sum of four consecutive integers is 198, the greatest integer is 51.
• The sum of four consecutive integers is 198, the product of them is 48 * 49 * 50 * 51 = 5997600.
• The sum of four consecutive integers is 198, the average of these integers is 49.5.
• The sum of four consecutive integers is 198, the sum of their squares is 482 + 492 + 502 + 512 = 9806.

## Summarize

On this page, In addition to introducing three methods how to find four consecutive integers whose sum is 198, it also provides a calculator that calculates four consecutive integers based on the sum. If you encounter a similar problem next time, you can directly use this calculator to calculate the answer, which is very convenient.

Of course, if the problem you encounter is more complicated, such as: the number of consecutive integers is not 4, or you need to calculate consecutive odd integers or even integers. You can use our other more advanced sum-based consecutive integers calculator, where you can specify the number of consecutive integers and select consecutive integers type: natural integers, odd integers or even integers. I believe it can help you.

Well, that’s it, the above are three solutions to find four consecutive integers whose sum is 198. It’s not very complicated, but I personally like the second method best, because it can accurately calculate the first integer and the calculation process is very simple. So how about you? Please leave a message and tell me which method you like?